Asked by Albert

hi i need help differentiating these..

1. y = cos(3x^2 + 2x)

2. y = ln(3x^2 + 5)

thank you
Answered by Steve
use the old chain rule:

y = cos(u)
y' = -sin(u) u' = -sin(3x^2+2x)(6x+2)

y = ln(u)
y' = 1/u u' = 1/(3x^2+5) * 6x = 6x/(3x^2+5)
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