Asked by Katie
You (65 kg) are standing in an elevator traveling upward that passes the 3rd floor at 3.5 m/s and then passes the 4th floor at 4.5 m/s one second later. Find the normal force exerted on your feet by the elevator while it is passing between these floors.
I got 6565 N, because acceleration is 1, Fnet = ma which is 65, and WE1 is -6500 N, but that isn't the right answer.
Thanks so much for any help you can give me!
I got 6565 N, because acceleration is 1, Fnet = ma which is 65, and WE1 is -6500 N, but that isn't the right answer.
Thanks so much for any help you can give me!
Answers
Answered by
drwls
The floor must accelerate the person as well as support his or her weight. Acceleration is upward at 1.0 m/s^2
I don't understand what your "WE1" is or how you came up with it.
F(on feet) = M*(g + a)
= 65*(9.8 + 1.0) = 702 N
I don't understand what your "WE1" is or how you came up with it.
F(on feet) = M*(g + a)
= 65*(9.8 + 1.0) = 702 N
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