Asked by Jackie
You have a total of 820 feet of fencing to enclose a large retangular larea and divide it into four smaller pens of the same dimensions. The fencing used to divide the large pen must be parallel to the same side of the large rectangle. Maximize the total rectangular area (other solutions found are not clear and one I believe to be wrong or really unclear)
Answers
Answered by
bobpursley
area= LW
820=2L+2W+3L
820=5L+2W or w=410-5/2 L
area=L(410-5/2 L)
darea/dL=0=(410-5/2L)+ L(-5/2)
solve for L, then W
820=2L+2W+3L
820=5L+2W or w=410-5/2 L
area=L(410-5/2 L)
darea/dL=0=(410-5/2L)+ L(-5/2)
solve for L, then W
Answered by
Amy
50l x 50 w
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