You have a total of 820 feet of fencing to enclose a large retangular larea and divide it into four smaller pens of the same dimensions. The fencing used to divide the large pen must be parallel to the same side of the large rectangle. Maximize the total rectangular area (other solutions found are not clear and one I believe to be wrong or really unclear)

Question

You have a total of 820 feet of fencing to enclose a large retangular larea and divide it into four smaller pens of the same dimensions.  The fencing used to divide the large pen must be parallel to the same side of the large rectangle.  Maximize the total rectangular area (other solutions found are not clear and one I believe to be wrong or really unclear)

bobpursley · Answer

area= LW 820=2L+2W+3L 820=5L+2W or w=410-5/2 L area=L(410-5/2 L) darea/dL=0=(410-5/2L)+ L(-5/2) solve for L, then W

Amy · Answer

50l x 50 w