Asked by brooke
                An 85 kg football player traveling 4.7 m/s is stopped in 1.0 s by a tackler. What is the original kinetic energy of the player? (I tried using 1/2 m v^2 but that doesn't seem to be right. How do I manipulate the formula?) What average power is required to stop him?
            
            
        Answers
                    Answered by
            bobpursley
            
    It is right, 1/2 m v^2 is the original KE.
average power= energy/timestopping
    
average power= energy/timestopping
                    Answered by
            Anonymous
            
    50 joules 
    
                    Answered by
            Anonymous
            
    934 joules
    
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