Question

A Football player on team a is movin gat a velocity of 8ms at an angle of 49 below the x axis. He collides with a player on team B, The Player B is moving at 7.5ms at an angle of 41 below the X and has a mass of 110KG after the collision both players remain in contact and move along the horizontal. what is the mass of player A.

so far i have M1 = M2= 110 V1=8 V2=7.5 V1'= V2'

Im not to sure about how to solve this one ?

Answer 1

I believe that you have mistake in given data: velocity of one of the players has to be ABOVE the x-axis. Assume that it is velocity of the player B. Now, y-projection of the law of conservation of linear momentuim gives
- m1•v1•cosα1+ m2•v2•cosαα2=0.
m1= m2•v2•cosαα2/ v1•cosα1 =110•7.5•sin41/8•sin49= 89.7 kg

Answer 2

Thanks alot, I guess my workbook does have a error as it clearly states both as below the horizontal.!