Asked by Chris
A wave is described by the equation y = (4.5×10−2) sin (1.9x − 3.2t), where lengths are measured in meters and time in seconds. What is the displacement of a particle at position x = 2.7 m at time t = 5.8 s? Note: Remember that the argument of the sine function in the wave equation is expressed in radians.
I don't have any idea
I don't have any idea
Answers
Answered by
Elena
y = (4.5•10^−2) sin (1.9x − 3.2t) =
= (4.5•10^−2) sin (1.9•2.7 − 3.2•5.8)=
=(4.5•10^−2) sin (5.13 − 18.56)=
=(4.5•10^−2) sin (5.13 − 18.56)=
=(4.5•10^−2) •0.76 = - 0.034 m
= (4.5•10^−2) sin (1.9•2.7 − 3.2•5.8)=
=(4.5•10^−2) sin (5.13 − 18.56)=
=(4.5•10^−2) sin (5.13 − 18.56)=
=(4.5•10^−2) •0.76 = - 0.034 m
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