y' = slope = m = 4 x
where x = -2, m = 4(-2) = -8
y = -8 x + b
at x = -2, y = 2(4) - 1 = 7
so
7 = -8(-2) + b
7 = 16 + b
b = - 9
so
y = -8 x - 9
Determine the equation of the tangent line to the curve y = 2x²-1 at the point where x = -2
2 answers
thank you