Question
two dice are tossed. find the probability that the sum is odd given that the sum is 5 or less
Answers
MathMate
A=sum is odd
B=sum is 5 or less
P(B)=|{(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(3,1),(3,2),(4,1)}|/36
=10/36
P(A∩B)=|{(1,1),(1,3),(2,1),(2,3),(3,2),(4,1)}|/36
=6/36
P(A|B)=P(A given B)
=P(A∩B)/P(B)
=?
B=sum is 5 or less
P(B)=|{(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(3,1),(3,2),(4,1)}|/36
=10/36
P(A∩B)=|{(1,1),(1,3),(2,1),(2,3),(3,2),(4,1)}|/36
=6/36
P(A|B)=P(A given B)
=P(A∩B)/P(B)
=?