If two "fair" dice are tossed what is the probability that the sum of their faces will be a multiple of 3? Show or explain how you got your answer?

Answer 1

possibilities
make a table
label 1 through 6 at top
label 1 through 6 down
you have 36 boxes
fill in the sums (1 through 12)
note symmetry and ease of filling in because every box is one plus the one to the left or above
a total of 12 of the 36 boxes holds a multiple of 3
12/36 = 1/3