Asked by Harrison
How many mols of dinitrogen monoxide are contained in 56.0L at STP?
Answers
Answered by
DrBob222
56.0L x (1 mol/22.4L) = ? mols.
Answered by
Mackenzie Tate
It is 2.50 moles if you are using significant digits!
56.0 L • 1 mol /22.4 L = 2.50 mol
56.0 L • 1 mol /22.4 L = 2.50 mol
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