Use the Henderson-Hasselbalch equation and the ICE chart below.
moles HPO4^2- = 0.193
moles H2PO4^- = 0.499
...........HPO4^2- + H^+ ==> H2PO4^-
initial....0.193......0.......0.499
add..................0.06...............chchange.....-0.06.....0.06......+0.06
equil.......0.133......0........0.493
Calculate pH when 0.060 mols of HCl are added to 1.000 L of a buffer containing 0.499M KH2PO4 and 0.193M K2HPO4
1 answer