Asked by frusterated
a block of mass 77kg is placed at the top of a frictionless plane that is inclined 46degrees to the horizontal. The height of the plane is 23 meters. find the speed of the block at the bottom of the plane.
Show the steps please,
-thanks
Show the steps please,
-thanks
Answers
Answered by
Henry
V^2 = Vo^2 + 2g*h
V^2 = 0 + 19.6*23 = 450.8
V = 21.2 m/s.
V^2 = 0 + 19.6*23 = 450.8
V = 21.2 m/s.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.