In a group of 7 men and 8 women, how many committees of 5 can be selected for which there are 2 men and 3 women? What is the probability of selecting a committee of 5 consisting of 2 men and 3 women?

Answer 1

C(7,2)*C(8,3) ways of choosing 2 out of 7 men and 3 out of 8 women. C(n,k) = n!/[(k!)(n-k)!]

C(15,5) ways of picking 5 committee members out of 15

probability of selecting 2 men and 3 women is good over total --

C(7,2)*C(8,3)/C(15,5)