From a group of eight women and seven men, a committee of six is chosen randomly. Find the probability that three women and three men will be chosen.

Answer 1

number of ways to choose 3 women from 8 is C(8,3) or 56
number of ways to choose 3 men from 7 is C(7,3) = 35
number of ways to choose 6 people from 15 is C(15,6) = 5005

so Prob(of stated situation) = 56(35)/5005 = 56/143