Asked by Leah
How would I evaluate these trig functions without using a calculator? U:
sin(-13π/6)
cot 11π/6
cot(-14π/4)
sec 23π/6
Thanks in advance ^^; and if you'd tell me step by step on how to do problems like these I'd be grateful :D
sin(-13π/6)
cot 11π/6
cot(-14π/4)
sec 23π/6
Thanks in advance ^^; and if you'd tell me step by step on how to do problems like these I'd be grateful :D
Answers
Answered by
Steve
sin(-θ) = -sinθ
sin(θ±2kπ) = sinθ
so, sin(-13π/6) = sin(-π/6) = -1/2
tan(θ±kπ) = tanθ -- same for cot
cot(11π/6) = cot(-π/6) = -cot(π/6) = -√3
cot(-14π/4) = cot(2π/4) = cot(π/2) = 0
sec(23π/6) = sec(-π/6) = √3/2
sin(θ±2kπ) = sinθ
so, sin(-13π/6) = sin(-π/6) = -1/2
tan(θ±kπ) = tanθ -- same for cot
cot(11π/6) = cot(-π/6) = -cot(π/6) = -√3
cot(-14π/4) = cot(2π/4) = cot(π/2) = 0
sec(23π/6) = sec(-π/6) = √3/2
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