This is soluble only if they both rods have the same mass distribution. If they do,
the center of mass of the 0.95 m rod is at (0.475; 0) and has a mass of 0.95;
the center of mass of the 1.8 m road is at (0; - 0.9) and has a mass of 1.8;
the center of mass of those two objects is at:
[(0.475)(0.95) + (0)(1.8)]/2.75 = 0.164 [x coordinate]
[(0)(0.95) + (-0.9)(1.8)]/2.75 = -0.589 [y coordinate]
C.M.: (0.164; -0.589)
A 0.95 m rod with uniform mass distribution runs along the x axis with its left end at the origin. A 1.8 m rod with uniform mass distribution runs along the y axis with its top end at the origin. Find the coordinates of the center of gravity for this system.
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