Asked by Anon
A uniform bar of mass 12 kg and length 1.4 m is held by a hinge on a vertical wall. A string is attached to the end so that the bar is in mechanical equilibrium. The angle between the bar and the string is 25o. Find the tension in the string.
Answers
Answered by
bobpursley
Summing moments about the hinge
12*g*1.4/2-Tension*1.4*sin25=0
Tension=12*9.8*.7 /(1.4*sin25)
12*g*1.4/2-Tension*1.4*sin25=0
Tension=12*9.8*.7 /(1.4*sin25)
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