A uniform bar of mass 12 kg and length 1.4 m is held by a hinge on a vertical wall. A string is attached to the end so that the bar is in mechanical equilibrium. The angle between the bar and the string is 25o. Find the tension in the string.

Answer 1

Summing moments about the hinge

12*g*1.4/2-Tension*1.4*sin25=0

Tension=12*9.8*.7 /(1.4*sin25)