Asked by Kayla
A 6.25 kg solid ball with a radius of 0.185 m rolls without slipping at 3.55 m/s. What is its total kinetic energy?
I didn't understand what the last person gave me for help can someone please help me!
I didn't understand what the last person gave me for help can someone please help me!
Answers
Answered by
Elena
KE = KE (translational) + KE (rotational)=
=m•v²/2 + I•ω²/2 =
= m•v²/2 +(2/5)•(m•R²/2)•(v²/R²) =
=0.7• m•v².
=m•v²/2 + I•ω²/2 =
= m•v²/2 +(2/5)•(m•R²/2)•(v²/R²) =
=0.7• m•v².
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.