Asked by Labz

Solve:
3^5x = 27^(x-1)

13 years ago

Answered by Henry

3^5x = 27^(x-1).
3^5x = (3^3)^(x-1)
3^5x = 3^(3(x-1))
3^5x = 3^(3x-3)
5x = 3x-3
5x-3x =-3
2x = -3
X = -3/2 = -1.5.

13 years ago

Answered by Labz

thank you!

13 years ago

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