caluclate the volume in mL of 1.74 grams of sodium chloride from a 0.270 M solution

Question

1.74g sodium chloride from a 0.270 M solution

7.10g ethonal from a 2.45 M solution

6.90g acetic acid (CH3COOH) from 0.606 M solution

Answer 1

For #1.
M = mols/L. You know M, you want to find L, that leaves moles that you don't know. How can you find that? That is mols NaCl = grams NaCl/molar mass NaCl. You know g and molar mass, solve for mols and substitute into the original M = mols/L. Solve for L and convert to mL.