Asked by dada78
how do I caluclate (H3O+) in a solution if the PH is the following 1.81
Answers
Answered by
DrBob222
pH = -log(H3O^+)
1.81 = -log(H3O^+).
Rearrange to -1.81 = log(H3O^+). Now
punch in -1.81 on your calculator (or 1.81 and hit the change sign button to make -1.81) then hit the 10<sup>x</sup> button. That will return 0.01549 and you can round that to 0.015 to two significant figures (two are allowed with the 1.81.)
1.81 = -log(H3O^+).
Rearrange to -1.81 = log(H3O^+). Now
punch in -1.81 on your calculator (or 1.81 and hit the change sign button to make -1.81) then hit the 10<sup>x</sup> button. That will return 0.01549 and you can round that to 0.015 to two significant figures (two are allowed with the 1.81.)
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