State the number of positive real zeros, negative real zeros, and imaginary zeros for g(x)= 9x3 -7x2+10x-4.

Question

Since there were 3 sign changes I have 3 positive real zeros.

For g(-x)= I have -9x3-7x2-10x-4. There were no sign changes so I have no negative real zeros.

The total number of positive real zeros therefore are 3 or 1, total number of negative real zeros is 0 and the total number of imaginary zeros is 0 or 2.

Is this correct?

Answer 1

Yes

Answer 2

Well-done!