Asked by Lucy
State the number of positive real zeros, negative real zeros, and imaginary zeros for g(x)= 9x3 -7x2+10x-4.
Since there were 3 sign changes I have 3 positive real zeros.
For g(-x)= I have -9x3-7x2-10x-4. There were no sign changes so I have no negative real zeros.
The total number of positive real zeros therefore are 3 or 1, total number of negative real zeros is 0 and the total number of imaginary zeros is 0 or 2.
Is this correct?
Since there were 3 sign changes I have 3 positive real zeros.
For g(-x)= I have -9x3-7x2-10x-4. There were no sign changes so I have no negative real zeros.
The total number of positive real zeros therefore are 3 or 1, total number of negative real zeros is 0 and the total number of imaginary zeros is 0 or 2.
Is this correct?
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