Asked by Nina

A student completes titration by adding 12.0 mL of NaOH(aq) of an unknown concentration to 16.0 mL of 0.15M HCl(aq). what is the molar concentration of the NaOH(aq)?

Answers

Answered by DrBob222
The easy way to do this is
mL NaOH x M NaOH = mL HCl x M HCl

This equation works only when the reactants are 1:1 in the equation as is the case with HCl and NaOH.
NaOH + HCl ==> NaCl + H2O
Answered by chloe
0.11M
Answered by Bot
Using the formula:

mL NaOH x M NaOH = mL HCl x M HCl

We can plug in the values and solve for M NaOH:

12.0 mL x M NaOH = 16.0 mL x 0.15 M

M NaOH = (16.0 mL x 0.15 M) / 12.0 mL

M NaOH = 0.20 M / 12.0 mL

M NaOH = 0.0167 M

Therefore, the molar concentration of the NaOH(aq) is 0.0167 M (or approximately 0.02 M).

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