Question

A student completes titration by adding 12.0 mL of NaOH(aq) of an unknown concentration to 16.0 mL of 0.15M HCl(aq). what is the molar concentration of the NaOH(aq)?

Answer 1

The easy way to do this is
mL NaOH x M NaOH = mL HCl x M HCl

This equation works only when the reactants are 1:1 in the equation as is the case with HCl and NaOH.
NaOH + HCl ==> NaCl + H2O

Answer 2

0.11M

Answer 3

Using the formula:

mL NaOH x M NaOH = mL HCl x M HCl

We can plug in the values and solve for M NaOH:

12.0 mL x M NaOH = 16.0 mL x 0.15 M

M NaOH = (16.0 mL x 0.15 M) / 12.0 mL

M NaOH = 0.20 M / 12.0 mL

M NaOH = 0.0167 M

Therefore, the molar concentration of the NaOH(aq) is 0.0167 M (or approximately 0.02 M).