Question
A student completes a titration by adding 12.0 milliliters of NaOH(aq) of unknown concentration to 16.0 milliliters of 0.15 M HCl(aq). What is the molar concentration of the NaOH(aq)?
Answers
Запишем уравнение реакции:
NaOH + HCl = NaCl + H2O
C NaOH*V NaOH = C HCl*V HCl
где: C NaOH и C HCl - молÑрные концентрации гидрокÑида Ð½Ð°Ñ‚Ñ€Ð¸Ñ Ð¸ хлорида водорода ÑоответÑтвенно, моль/л; V NaOH и V HCl - объемы раÑтворов гидрокÑида Ð½Ð°Ñ‚Ñ€Ð¸Ñ Ð¸ ÑолÑной киÑлоты ÑоответÑтвенно, л.
МолÑÑ€Ð½Ð°Ñ ÐºÐ¾Ð½Ñ†ÐµÐ½Ñ‚Ñ€Ð°Ñ†Ð¸Ñ NaOH равна:
C NaOH*V = C HCl*V HCl/V NaOH = 0,016*0,15/0,012 = 0,2 моль/л
We write the reaction equation:
NaOH + HCl = NaCl + H2O
C NaOH * V NaOH = C HCl * V HCl
where: C NaOH and C HCl - molar concentration of sodium hydroxide and hydrogen chloride, respectively, mol / l; V NaOH and V HCl - volumes of the solutions of sodium hydroxide and hydrochloric acid, respectively, l.
Molar concentration of NaOH is:
C NaOH * V = C HCl * V HCl / V NaOH = 0,016 * 0,15 / 0,012 = 0,2 mol / l
NaOH + HCl = NaCl + H2O
C NaOH*V NaOH = C HCl*V HCl
где: C NaOH и C HCl - молÑрные концентрации гидрокÑида Ð½Ð°Ñ‚Ñ€Ð¸Ñ Ð¸ хлорида водорода ÑоответÑтвенно, моль/л; V NaOH и V HCl - объемы раÑтворов гидрокÑида Ð½Ð°Ñ‚Ñ€Ð¸Ñ Ð¸ ÑолÑной киÑлоты ÑоответÑтвенно, л.
МолÑÑ€Ð½Ð°Ñ ÐºÐ¾Ð½Ñ†ÐµÐ½Ñ‚Ñ€Ð°Ñ†Ð¸Ñ NaOH равна:
C NaOH*V = C HCl*V HCl/V NaOH = 0,016*0,15/0,012 = 0,2 моль/л
We write the reaction equation:
NaOH + HCl = NaCl + H2O
C NaOH * V NaOH = C HCl * V HCl
where: C NaOH and C HCl - molar concentration of sodium hydroxide and hydrogen chloride, respectively, mol / l; V NaOH and V HCl - volumes of the solutions of sodium hydroxide and hydrochloric acid, respectively, l.
Molar concentration of NaOH is:
C NaOH * V = C HCl * V HCl / V NaOH = 0,016 * 0,15 / 0,012 = 0,2 mol / l