Vp = 200mi/h @ 180.
Vw = 25mi/h @ 240 Deg.
1. X=Hor=200*cos180+25*cos240=-212.5 mi/h
Y=Ver=200*sin180+25*sin240=-21.65mi/h
Vp=sqrt((-212.50^2)+(-21.65)^2)=213.6
= Velocity of plane.
2. tanA = Y/X = -21.65 / -212.5 = 0.10188.
A = 5.8 Deg. = Smallest angle.
3. C = 90 = Largest angle.
4. B=90-5.8 = 84.2 Deg.= Remaining angle.
5. Bearing = 180 + 5,8=185.8 Deg.,CCW
= 5.8 Deg. South of West
4. C = 180 - 5.8 - 84.2 = 90 Deg
A plane is heading west at 200 mph. The wind is blowing S30°W at 25 mph.
1. What is the ground speed of the plane?
2. When you solve the triangle, what is the smallest angle?
3. What is the largest angle of the triangle?
4. What is the remaining angle?
5. What is the bearing of the plane?
Please help out if you can, thanks. <3
1 answer
2 answers