Question
A plane has a speed of 250mph and flies with a bearing of N35degE. The wind is blowing from the west at 25 mph with a heading of due east. What is the actual speed and heading of the plane? Round to one decimal place.
Answers
250 @ N35E = (143.4,204.8)
25 @ E = (25,0)
add them to get
(168.4,204.8) = 265.1 @ N39.5E
25 @ E = (25,0)
add them to get
(168.4,204.8) = 265.1 @ N39.5E
Vpw = Vp + Vw = 250[N35oE] + 25 =
250*sin35 + i250*Cos35 + 25 =
143.4 + 204.8i + 25 = 168.4 + 204.8i =
265mi/h[N50.6oE].
250*sin35 + i250*Cos35 + 25 =
143.4 + 204.8i + 25 = 168.4 + 204.8i =
265mi/h[N50.6oE].
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