Asked by matematicass
what angle between vectors u = 2j+2k & v= 3i+4k
Gracias por ayudarme
Gracias por ayudarme
Answers
Answered by
Steve
u.v = |u| * |v| * cosθ
cosθ = (6+8)/(2√2)(5) = 14/10√2
θ = 8.13°
cosθ = (6+8)/(2√2)(5) = 14/10√2
θ = 8.13°
Answered by
Count Iblis
u dot v = |u| |v| cos(theta)
u dot v = 6
|u| = 2 sqrt(2)
|v| = 5
cos(theta) = 3/[5 sqrt(2)]
u dot v = 6
|u| = 2 sqrt(2)
|v| = 5
cos(theta) = 3/[5 sqrt(2)]
Answered by
Count Iblis
Correction u dot v = 8, so
cos(theta) = 4/[5 sqrt(2)]
cos(theta) = 4/[5 sqrt(2)]
Answered by
matematicas
but isn't is a three dimensional vectors
Answered by
Steve
my bad. I misread the problem.
Count Iblis is correct.
Count Iblis is correct.