Asked by star
a man 60 kg skating with a speed of 10 m/s collides with 40 kg skater at rest and they cling to eachother. Find the loss in kinetic energy?
Answers
Answered by
bobpursley
figure initial KE
1/2 60 10^2=
final KE
momentum.. (60+40)V=60*10 V= 6m/s
final ke then 1/2 100*6^2
you figure the loss.
1/2 60 10^2=
final KE
momentum.. (60+40)V=60*10 V= 6m/s
final ke then 1/2 100*6^2
you figure the loss.
Answered by
milind
1800J
Answered by
Farris
Bobpursley can u write it for me in a better way than what you have written
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