the women exert the same force on the man but in the opposite direction so if the women's net force exerted by man=-210(west) so the man's net force exerted by woman(a)=210 N (east)
Fnet=ma
210=94a,acceleration of the man (c)a=210/94
acceleration of the woman (b)f=ma
-210=54a
a=-210/54 the acceleration should be negative because the woman is moving west
A 58 kg woman is ice-skating toward the east on a frictionless frozen lake when she collides with a 94 kg man who is ice-skating toward the west. The maximum force exerted on the woman by the man during the collision is 210 N, west. Take east to be the positive direction of the x axis. (a) What is the maximum force on the man from the woman, including direction? (b) What is the maximum acceleration of the woman, including direction? (c) What is the maximum acceleration of the man, including direction?
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1 answer