Asked by james

Find the diameter of a gold coin that has a weight of 1.00 (troy) oz and a thickness of 3.00 mm.
Answered by bobpursley
mass= density*volume= density*thickness*PI*radius squared.

solve for diameter (twice radius)
Answered by thomas
they wanted the answer in cm to ---------> cm. (1.00 oz = 28.35 g).
Answered by thomas
so do i still solve it the same way
Answered by bobpursley
You have to work in consistent units. I have no idea what you are using for units in density. Make consistent units, then convert the answer to cm.
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