Asked by myra
An 8.0 kg puck floating on an air table is travelling east at 15 cm/s. Coming the other way at 25 cm/s is a 2.0 kg puck on which is affixed a wad of bubble gum. The two slam head-on into each other and stick together. Find their velocity after the impact. How much kinetic energy was lost?
Answers
Answered by
Wonnie
m1v1+m2v2 = v'(m1+m2)
This is the equation you must use so...
(8*15)+(2*(-25)) = v'(8+2)
The velocity for 25cm/s is negative because it's approaching the first puck in the opposite direction. Just find v' to find the velocity after impact.
Not sure for lost KE. Sorry.
This is the equation you must use so...
(8*15)+(2*(-25)) = v'(8+2)
The velocity for 25cm/s is negative because it's approaching the first puck in the opposite direction. Just find v' to find the velocity after impact.
Not sure for lost KE. Sorry.
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