Asked by Vilma
The area of a rectangle is 48 square cm. If the length is 8 cm greater than the width, what are the dimension of the rectangle?
Answers
Answered by
bobpursley
(w+8)w=48
solve for w
solve for w
Answered by
Bosnian
w = width
l = length
A = Area
l = w + 8
A = l * w
A = ( w + 8 ) * w = 48
w ^ 2 + 8 w = 48 Subtract 48 to both sides
w ^ 2 + 8 w - 48 = 48 - 48
w ^ 2 + 8 w - 48 = 0
The exact solutions are :
w = 4
and
w = - 12
Width can't be negative so :
w = 4 cm
l = w + 8
l = 4 + 8 = 12 cm
A = l * w
A = 12 * 4 = 48 cm ^ 2
P.S.
If you don't know how to solve equation :
w ^ 2 + 8 w - 48 = 0
In google type:
quadratic equation online
When you see list of results click on:
Free Online Quadratic Equation Solver:Solve by Quadratic Formula
When page be open in rectangle type:
w ^ 2 + 8 w - 48 = 0
and click option: solve it
You will see solution step-by step
l = length
A = Area
l = w + 8
A = l * w
A = ( w + 8 ) * w = 48
w ^ 2 + 8 w = 48 Subtract 48 to both sides
w ^ 2 + 8 w - 48 = 48 - 48
w ^ 2 + 8 w - 48 = 0
The exact solutions are :
w = 4
and
w = - 12
Width can't be negative so :
w = 4 cm
l = w + 8
l = 4 + 8 = 12 cm
A = l * w
A = 12 * 4 = 48 cm ^ 2
P.S.
If you don't know how to solve equation :
w ^ 2 + 8 w - 48 = 0
In google type:
quadratic equation online
When you see list of results click on:
Free Online Quadratic Equation Solver:Solve by Quadratic Formula
When page be open in rectangle type:
w ^ 2 + 8 w - 48 = 0
and click option: solve it
You will see solution step-by step
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