Asked by j
                3. Determine that the vectors u=[t, 4, 2t+1] and v=[t+2, 1-t, -1] are perpendicular, find the possible values of the contant, t.
            
            
        Answers
                    Answered by
            MathMate
            
    Same as previous question, 
http://www.jiskha.com/display.cgi?id=1337914331
Except that the dot-product equated to zero results in a quadratic equation.
So solve for possible values of t by solving the quadratic.
    
http://www.jiskha.com/display.cgi?id=1337914331
Except that the dot-product equated to zero results in a quadratic equation.
So solve for possible values of t by solving the quadratic.
                    Answered by
            j
            
    t(t+2) + 4(1-t) - (2t+1) = 0 
t = 1,3
like that?
    
t = 1,3
like that?
                    Answered by
            MathMate
            
    Correct!
    
                    Answered by
            j
            
    thanks
    
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