Asked by Ethan
An external force F is holding a bob of mass 725 g in a stationary position. The angle that the massless rope makes with the vertical is θ = 33°.
(a) What is the magnitude, F, of the force needed to maintain equilibrium in N?
(b) What is the tension in the rope in N?
(a) What is the magnitude, F, of the force needed to maintain equilibrium in N?
(b) What is the tension in the rope in N?
Answers
Answered by
Elena
F =T•sinα ,
mg = T•cos α..
F/m•g = tan α,
F = m•g•tan α =0.725•9.8•0.65 =4.6 N,
T =F/sinα = 4.6/0.54 = 8.45 N.
mg = T•cos α..
F/m•g = tan α,
F = m•g•tan α =0.725•9.8•0.65 =4.6 N,
T =F/sinα = 4.6/0.54 = 8.45 N.
Answered by
Ethan
I understand how the first and third equations are used to find the answers, but how is the second equation (mg = Tcosa) used?
Answered by
Elena
The third equation is the result of division the first equation by the second equation
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