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A railroad car moves under a grain elevator at a constant speed of 4.10 m/s. Grain drops into the car at the rate of 660 kg/min...Asked by Dan
A railroad car moves under a grain elevator at a constant speed of 3.70 m/s. Grain drops into the car at the rate of 580 kg/min. What is the magnitude of the force needed to keep the car moving at constant speed if friction is negligible?
F = Ma -> R * V(rel)
F = Ma -> R * V(rel)
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Answered by
Dan
Sorry - got cut off. I meant to supply
R * V(rel) = Ma
R * V(rel) = Ma
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