Question
ok here we go ... its a series-parellel circuit with 5 resistors.
12 volt battery- wire goes up then one wire branches up at 45 deg with a 10 ohm resistor then down at a 45 deg with a 10 ohm resistor, a second wire branches down at 45 deg with a 20 ohm resistor then up at a 45 deg with a 25 ohm resistor, now both wires join up again as one (kinda looks like a leaf) and into a 50 ohm resistor and back to the battery
Looking for how to solve this one to find the current for each, the voltage for each and the power consumed by each..
12 volt battery- wire goes up then one wire branches up at 45 deg with a 10 ohm resistor then down at a 45 deg with a 10 ohm resistor, a second wire branches down at 45 deg with a 20 ohm resistor then up at a 45 deg with a 25 ohm resistor, now both wires join up again as one (kinda looks like a leaf) and into a 50 ohm resistor and back to the battery
Looking for how to solve this one to find the current for each, the voltage for each and the power consumed by each..
Answers
bobpursley
If I am reading it correctly, you have a parallel circuit in which two series branches are in parallel.
The resistance of the series branches are 20 ohm(10+10), and 45 ohm(20+25). Those in parallel offer a total resistance of
Rp=20*45/(20+45) figure that out.
Then, that is in series with the 50 ohm resitor.
Find total current. Find voltage across the 50 ohm resistor (Itotal*50).
Now you know voltage across the parallel branch, so you can easily find current in each branch.
The resistance of the series branches are 20 ohm(10+10), and 45 ohm(20+25). Those in parallel offer a total resistance of
Rp=20*45/(20+45) figure that out.
Then, that is in series with the 50 ohm resitor.
Find total current. Find voltage across the 50 ohm resistor (Itotal*50).
Now you know voltage across the parallel branch, so you can easily find current in each branch.
Dave
Hi Bob, just to make sure... I figure out the top and bottom .. and not the left and right .. is that correct?