Asked by barbie
1. a car starts from rest attains a velocity of 36kmph with an acceleration of 0.1 m/s^2 find the total time of travel of the car.
2. the distance travelled by a body in fourth second is twice the distance travelled in second of the acceleration of the body is 3m/s^2 the find initial velocity of the body
2. the distance travelled by a body in fourth second is twice the distance travelled in second of the acceleration of the body is 3m/s^2 the find initial velocity of the body
Answers
Answered by
bobpursley
vf=at solve for t.
distanceinfourthsecond= d(4)-d(3)
= vi*4+1/2 3 4^2-vi*3-1/2 3 3^2
= vi+ 1/2 3*(16-9)
do the same thing to get distance during second.
distanceinfourthsecond= d(4)-d(3)
= vi*4+1/2 3 4^2-vi*3-1/2 3 3^2
= vi+ 1/2 3*(16-9)
do the same thing to get distance during second.
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