Asked by Clinton
A car starts from rest and attains a velocity of 40 metres per second in 20 seconds. it maintains this velocity for 30 seconds and then comes to rest in 25 seconds.
1. sketch the velocity time graph for the motion.
2. Calculate the acceleration of the body.
3. Calculate the total distance covered by the body
1. sketch the velocity time graph for the motion.
2. Calculate the acceleration of the body.
3. Calculate the total distance covered by the body
Answers
Answered by
Steve
acceleration= changevelocity/time
Answered by
Damon
first 20 s
slope of v = a = 2 m/s^2
v = 0 + 2 t
x = (1/2)(2) t^2
at t = 20
v = 40 m/s
x = 400 m
from t = 20 to t = 50
v = 40 m/s
a = 0
at t = 50
v = 40
new a = -40/25
x = 400 + 40(30) = 1600
from t = 50 to t = 75
v = 40 - 40/25(t-50)
a = -40/25
x = 1600 +40(t-50) - 20/25(t-50)^2
x = 1600 + 20*25 = 2100 at end
slope of v = a = 2 m/s^2
v = 0 + 2 t
x = (1/2)(2) t^2
at t = 20
v = 40 m/s
x = 400 m
from t = 20 to t = 50
v = 40 m/s
a = 0
at t = 50
v = 40
new a = -40/25
x = 400 + 40(30) = 1600
from t = 50 to t = 75
v = 40 - 40/25(t-50)
a = -40/25
x = 1600 +40(t-50) - 20/25(t-50)^2
x = 1600 + 20*25 = 2100 at end
Answered by
Anonymous
AE=40
EO=20=2ms-2
EO=20=2ms-2
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