solve csc^2x - cscx + 9 =11

1 answer

csc ^ 2 ( x ) - csc ( x ) + 9 = 11 Subtract 11 to both sides

csc ^ 2 ( x ) - csc ( x ) + 9 - 11 = 11 - 11

csc ^ 2 ( x ) - csc ( x ) - 2 = 0

Substitute :

csc ( x ) = u

u ^ 2 - u - 2 = 0

The exact solutions are :

u = - 1

and

u = 2

u = csc ( x ) so :

csc ( x ) = - 1

and

csc ( x ) = 2

csc ( - pi / 2 ) = - 1

csc ( x ) is a periodic function with period 2 pi n

where n is an integer

Solutions :

x = 2 pi n - pi / 2

and

x = 2 pi n - pi / 2 + 2 pi =

2 pi n - pi / 2 + 4 pi / 2 =

2 pi n + 3 pi / 2

csc ( pi / 6 ) = 2

csc ( 5 pi / 6 ) = 2

csc ( x ) is a periodic function with period 2 pi n

where n is an integer

Solutions :

x = 2 pi n + pi / 6

and

x = 2 pi n + 5 pi / 6

Final solutions :

x = 2 pi n - pi / 2

x = 2 pi n + 3 pi / 2

x = 2 pi n + pi / 6

x = 2 pi n + 5 pi / 6

P.S

If you don't know how to solve equation

u ^ 2 - u - 2 = 0

In google type:

quadratic equation online

When you see list of results click on:

Free Online Quadratic Equation Solver:Solve by Quadratic Formula

When page be open in rectangle type:

u ^ 2 - u - 2 = 0

and click option: solve it

You will see solution step-by step
Similar Questions
  1. integral of cscx^(2/3)(cot^3)xi know that cot^2x is csc^2(x)-1, but i just don't understand how to solve the cscx^(2/3), any
    1. answers icon 1 answer
  2. express in sinx1 1 ---------- + -------- cscx + cotx cscx - cotx and express in cosx 1 + cot x ------- - sin^2x cscx = 1/sinx so
    1. answers icon 0 answers
  3. Find a numerical value of one trigonometric function of x iftanx/cotx - secx/cosx = 2/cscx a) cscx=1 b) sinx=-1/2 c)cscx=-1
    1. answers icon 1 answer
    1. answers icon 2 answers
more similar questions