Asked by Megan
Enthalpy changes:
H2O2(l) ----> H2O(l) + 1/2P2(g) delta H= -94.6kJ
H2(g) + 1/2O2(g)----> H2O2 delta H= -286.0kJ
Calculate the value on delta H for the reaction:
H2(g) + H2O2(l)----> 2H2O(l)
H2O2(l) ----> H2O(l) + 1/2P2(g) delta H= -94.6kJ
H2(g) + 1/2O2(g)----> H2O2 delta H= -286.0kJ
Calculate the value on delta H for the reaction:
H2(g) + H2O2(l)----> 2H2O(l)
Answers
Answered by
Anonymous
−187.6 kJ/mol
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