Question

Enthalpy changes:
H2O2(l) ----> H2O(l) + 1/2P2(g) delta H= -94.6kJ
H2(g) + 1/2O2(g)----> H2O2 delta H= -286.0kJ

Calculate the value on delta H for the reaction:
H2(g) + H2O2(l)----> 2H2O(l)

Answer 1

−187.6 kJ/mol