Asked by Pat
The strength of an electric field at 5.0 cm from a point charge is 100.0 N/C. What is the magnitude of the source charge? Show work so I understand how to do it.
Answers
Answered by
bobpursley
E=kQ/r^2
solve for Q, you have r, E
solve for Q, you have r, E
Answered by
Pat
If I knew how to do it with formula I would have done it.
Answered by
drwls
Rearrange the formula to calculate Q, using algebra. You get
Q = r^2*E/k
k = 8.99*10^9 N*m^2/C^2
(a constant of nature)
E = 100 N/C
r = 0.05 m
Just crank out the number. It will be in Coulombs.
Q = r^2*E/k
k = 8.99*10^9 N*m^2/C^2
(a constant of nature)
E = 100 N/C
r = 0.05 m
Just crank out the number. It will be in Coulombs.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.