Asked by Sarah
The differential of the function y=(x^2+9)^3 is
dy=_________ dx.
When x=3 and dx=005, the differential dy=_________
dy=_________ dx.
When x=3 and dx=005, the differential dy=_________
Answers
Answered by
Steve
dy = 3(x^2+9)^2 * 2x dx = 6x(x^2+9)^2 dx
dy = 6(3)(18^2)(1/200) = 729/25 = 29.16
dy = 6(3)(18^2)(1/200) = 729/25 = 29.16
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