Asked by steeven
(a) if a train travelling at 72km/hr is to be brought to rest in a distance of 200m then wat should be its retardation
(b) if a body starts from rest and and travels 120 m in 8th sec then wats its acceleration.
(b) if a body starts from rest and and travels 120 m in 8th sec then wats its acceleration.
Answers
Answered by
drwls
(a) How do you define retardation?
Is it deceleration?
72 km/h = 20 m/s
Average velocity during deceleration = 10 m/s.
10*t = 200 m
Deceleration time t = 20 s
Deceleration rate = 20 m/s/20s
= 1 m/s^2
(b) If you are supposed to assume the acceleration rate is constant,
X(8) - X(7) = (a/2)*(64-49)
= 120
15*(a/2) = 120
a = 16 m/s^2
Is it deceleration?
72 km/h = 20 m/s
Average velocity during deceleration = 10 m/s.
10*t = 200 m
Deceleration time t = 20 s
Deceleration rate = 20 m/s/20s
= 1 m/s^2
(b) If you are supposed to assume the acceleration rate is constant,
X(8) - X(7) = (a/2)*(64-49)
= 120
15*(a/2) = 120
a = 16 m/s^2
Answered by
Anonymous
A motor car moving with a velocity of 54km/hr is brought to rest in (i) 5sec (ii) 3meter. Find the retardation in each case.
Answered by
Umair
10*t = 200 m
this is wrong ????? because velocity is 20m/s
this is wrong ????? because velocity is 20m/s
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