Umair
This page lists questions and answers that were posted by visitors named Umair.
Questions
The following questions were asked by visitors named Umair.
the velocity of the body moving in a straight line with a constant acceleration, is 10 m/s at a certain instant 't' . after 5 second the velocity become 20 m/s, the velocity 3 second before 't' was?
10 years ago
The average Fahrenheit temperature in Fairbanks, Alaska, during a typical 365-days year. The equation that approximates the temperature on day 𝑥 is 𝑦 = 37𝑠𝑖𝑛 [(2𝜋/365)(𝑥 − 101)] + 25 i. On what day is the temperature increasing the fastest? ii. About how...
5 years ago
Answers
The following answers were posted by visitors named Umair.
28.5
11 years ago
Your Program is fine. I have compiled it. It is working. Whats your problem. For any query you can contact me. I can provide you free online tutoring.
9 years ago
You can whatsapp me 00923215081005
9 years ago
#include<iostream.h> #include<conio.h> int main () { float noosec; float distmiles; cout<<"Enter number of sec between lightning and thunder:"<<endl; cin>>noosec; distmiles=noosec/5; cout<<"Distance is:"<<endl; cout<<distmiles<<endl; return 0; } This is m...
9 years ago
I can help you on this by sharing screen. Plz whatsapp me if you are interested 00923215081005
9 years ago
I can do this project for you please contact me 00923215081005
8 years ago
I will give you guide or teach you concept relating to this but I will not tell you whole project just guide... My whatsapp 00923215081005
8 years ago
10*t = 200 m this is wrong ????? because velocity is 20m/s
8 years ago
Let 'a' be the original value of the first car, Let 'b' be the original value of the second car Car A: Final = Original(Rate)^t1 0.6a = a(0.9)^t1 0.6 = 0.9^t1 t1 = (Log0.6)/(Log0.9) t1 = 4.85 Car B: 0.6b = b(0.85)^t2 0.6 = 0.85^t2 t2 = (Log0.6)/(Log0.85)...
5 years ago