Asked by Brad
A package contains 12 resistors, 3 of which are defective. If four are selected, find the
probability of getting the following.
No defective resistors
One defective resistors
3 defective resistors
probability of getting the following.
No defective resistors
One defective resistors
3 defective resistors
Answers
Answered by
PsyDAG
Assuming no replacement,
The probability of both/all events occurring is determined by multiplying the probabilities of the individual events.
None defective = 9/12 * 8/11 * 7/10 * 6/9 = ?
One defective = 3/12 * 9/11 * 8/10 * 7/9 = ?
Three defective = 3/12 * 2/11 * 1/10 * 9/9 = ?
The probability of both/all events occurring is determined by multiplying the probabilities of the individual events.
None defective = 9/12 * 8/11 * 7/10 * 6/9 = ?
One defective = 3/12 * 9/11 * 8/10 * 7/9 = ?
Three defective = 3/12 * 2/11 * 1/10 * 9/9 = ?
Answered by
Bibi
a record company claims that of 55 000 cd's produced 15% will be defective, 100 were defective. is the company right?
Answered by
Anonymous
adf
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