Question
It's a molar heat reaction lab.
0.07g Mg
Mg+2HCl->MgCl2+H2
What is the actual value for the heat of reaction based on the enthalpy's of formation?
HfHCl= -118.53 kJ/mole
HfMgCl2= -774 kJ/mole
0.07g Mg
Mg+2HCl->MgCl2+H2
What is the actual value for the heat of reaction based on the enthalpy's of formation?
HfHCl= -118.53 kJ/mole
HfMgCl2= -774 kJ/mole
Answers
DrBob222
dHrxn = (n*dHf MgCl2) - (dHf HCl) = ?