Asked by Lucas
Calculate the volume of a square pyramid if it has a base area of 64 cm^2 and the distance from the apex to a corner of the base is 15 cm.
Thank you so much!!!
Thank you so much!!!
Answers
Answered by
drwls
Base length = a = sqrt64 = 8 cm
Distance from corner to center of base
= a*sqrt2 = 11.314 cm
Pyramid height =
h = sqrt[15^2 -(8sqrt2)^2]
= sqrt[225 - 128]= 9.85 cm
Volume = (base area)*(height)/3
= 210 cm^3
Distance from corner to center of base
= a*sqrt2 = 11.314 cm
Pyramid height =
h = sqrt[15^2 -(8sqrt2)^2]
= sqrt[225 - 128]= 9.85 cm
Volume = (base area)*(height)/3
= 210 cm^3
Answered by
MathMate
Side of base = √64 = 8 cm
Distance from centre to corner of base
=8(√2)/2=4√2
Let h=height,
h²=15²-(4√2)²
=225-32=193
h=√193 = 13.89 cm approx.
Volume
=(64)h/3
=64*(√193)/3
=296.4 cm³ approx.
Distance from centre to corner of base
=8(√2)/2=4√2
Let h=height,
h²=15²-(4√2)²
=225-32=193
h=√193 = 13.89 cm approx.
Volume
=(64)h/3
=64*(√193)/3
=296.4 cm³ approx.
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