Asked by eddie
Calculate the volume of 1.00 M acetic acid solution and mass of sodium acetate needed to make 250 mL of a 0.450 M acetic acid/acetate buffer solution with a pH of 4.00. (The pKa is 4.74 for acetic acid).
Answers
Answered by
DrBob222
I work these buffer problems with millimols instead of M.
You want 250 mL x 0.450M = 112.5 millimols of the buffer.
so equation 1 is base + acid = 112.5
Equation 2 comes from the HH equation.
pH = pKa + log (base)/(acid)
4.00 = 4.74 + log b/a
Solve for b/a and rearrange to
base = ?*a. This is equation 2.
Solve the two equations simultaneously for millimols base and acid, then convert mmols acid to mL of the 1.0 M and convert mmols base to g NaAc.
You want 250 mL x 0.450M = 112.5 millimols of the buffer.
so equation 1 is base + acid = 112.5
Equation 2 comes from the HH equation.
pH = pKa + log (base)/(acid)
4.00 = 4.74 + log b/a
Solve for b/a and rearrange to
base = ?*a. This is equation 2.
Solve the two equations simultaneously for millimols base and acid, then convert mmols acid to mL of the 1.0 M and convert mmols base to g NaAc.
Answered by
Camillo
Dr bob can you please elaborate a little more I struggling to put it together
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.