Question

The operating potential difference of a light bulb is 120 V. The power rating of the bulb is 105 W. Find the current in the bulb and the bulb's resistance.
Current
1 A
Resistance
2

I got 0.916 for A
and 115 for B but they are wrong

Answer 1

P=I•U ,
I =P/U =105/120 =0.875 A
P =I²•R,
R=P/I² =105/120²=7.3•10^-3 Ω

Answer 2

the second answer is supposed to be in the hundreds

Answer 3

7.3•10^-3 = 0.0073