Asked by trig identities
cos x (sec x +cos x csc2x)=csc2x
Answers
Answered by
bobpursley
cosx secx=1
cos^2 *csc^2= ctn^2 x
1+ctn^2=csc^2
multipy left by sin^2/sin^2
1/sin^2 (sin^2+cos^2)=
csc^2 = csc^2
cos^2 *csc^2= ctn^2 x
1+ctn^2=csc^2
multipy left by sin^2/sin^2
1/sin^2 (sin^2+cos^2)=
csc^2 = csc^2
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